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Efficiency of a Heat Engine

πŸ“Š intermediate
$$\eta = 1 - \frac{Q_L}{Q_H}$$
Measures the fraction of heat energy converted into useful work.
Variables & Units
$\eta$
Efficiency
Unit: Ratio (0 to 1)
$Q_H$
Heat absorbed from hot reservoir
Unit: Joule ($J$)
$Q_L$
Heat rejected to cold reservoir
Unit: Joule ($J$)
Key Information
πŸ“ Derived From
First and Second Laws of Thermodynamics.
πŸ’‘ Example
Engine taking $1000 J$ of heat and outputting $400 J$ of work has $40\%$ efficiency.
πŸ”§ Applications
Automotive engineering and power plants.
⚠️ Constraints
Cannot be $100\%$ efficient due to Second Law.

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